[ACCEPTED]-Looking for values in nested tuple-python
The elements of a tuple can be extracted 5 by specifying an index: ('a', 'b')[0] == 'a'. You can use a 4 list comprehension to iterate over all elements of some iterable. A 3 tuple is also iterable. Lastly, any() tells whether 2 any element in a given iterable evaluates 1 to True. Putting all this together:
>>> t = (
... ('dog', 'Dog'),
... ('cat', 'Cat'),
... ('fish', 'Fish'),
... )
>>> def contains(w, t):
... return any(w == e[0] for e in t)
...
>>> contains('fish', t)
True
>>> contains('dish', t)
False
Try:
any('fish' == tup[0] for tup in t)
EDIT: Stephan is right; fixed 'fish' == tup[0]. Also 1 see his more complete answer.
When you have an iterable of key-value pairs 4 such as:
t = (
('dog', 'Dog'),
('cat', 'Cat'),
('fish', 'Fish'),
)
You can "cast" it to a 3 dictionary using the dict() constructor, then 2 use the in keyword.
if 'fish' in dict(t):
print 'fish is in t'
This is very similar to 1 the above answer.
You could do something like this:
if 'fish' in (item[0] for item in t):
print "Fish in t."
or this:
if any(item[0] == 'fish' for item in t):
print "Fish in t."
If 3 you don't care about the order but want 2 to keep the association between 'dog' and 'Dog', you 1 may want to use a dictionary instead:
t = {
'dog': 'Dog',
'cat': 'Cat',
'fish': 'Fish',
}
if 'fish' in t:
print "Fish in t."
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