[ACCEPTED]-Variable defined with with-statement available outside of with-block?-python
Yes, the context manager will be available 3 outside the with statement and that is not 2 implementation or version dependent. with 1 statements do not create a new execution scope.
the with syntax:
with foo as bar:
baz()
is approximately sugar for:
try:
bar = foo.__enter__()
baz()
finally:
if foo.__exit__(*sys.exc_info()) and sys.exc_info():
raise
This 2 is often useful. For example
import threading
with threading.Lock() as myLock:
frob()
with myLock:
frob_some_more()
the context 1 manager may be of use more than once.
In case f is a file, it will be appear closed 4 outside the with statement.
For example, this
f = 42
print f
with open('6432134.py') as f:
print f
print f
would 3 print:
42
<open file '6432134.py', mode 'r' at 0x10050fb70>
<closed file '6432134.py', mode 'r' at 0x10050fb70>
You can find the details in PEP-0343 under 2 the section Specification: The 'with' Statement. Python scope rules (which might be irritating) apply to 1 f as well.
To answer Heikki's question in the comments: yes, this 4 scoping behavior is part of the python language 3 specification and will work on any and all 2 compliant Pythons (which includes PyPy, Jython, and 1 IronPython).
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