[ACCEPTED]-Applying a method with no return value to each element of a list-list-comprehension
No - list comprehensions are meant to be 18 use with functions having return values. It's 17 how their semantics are defined:
List comprehensions 16 provide a concise way to create lists 15 without resorting to use of map(), filter() and/or lambda. The 14 resulting list definition tends often 13 to be clearer than lists built using those 12 constructs. Each list comprehension consists 11 of an expression followed by a for clause, then 10 zero or more for or if clauses. The result 9 will be a list resulting from evaluating 8 the expression in the context of the for 7 and if clauses which follow it.
Having 6 read this, it should be clear that "a 5 list comprehension from a function having 4 no return value" is an oxymoron.
Just 3 use a for loop for something "one off":
import random
L = []
for x in range(5):
l = range(5)
random.shuffle(l)
L.append(l)
Clean 2 and simple. Your shuffled function is also just 1 fine, and can be used in a list comprehension.
Eli is quite right. But I'd go for something 1 more concise:
import random
L = [range(5) for each in xrange(5)]
for each in L:
random.shuffle(each)
[edit]
OTOH you could use random.sample():
from random import sample
xr = xrange(5)
L = [sample(xr, 5) for each in xr]
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