[ACCEPTED]-How to escape $ in PHP using preg_replace?-preg-replace

Accepted answer

Score: 16

I would strongly recommend using preg_quote() instead.

Score: 7

The correct answer is that you must escape 4 the backslash and the dollar sign in the 3 regex using PHP's escape characters.

backslash = \\
dollar sign = \$

$tmpStr=preg_replace("/\\\$/", "\\$", $tmpStr);

This 2 is useful for anyone that needs to match 1 a string that contains a dollar sign.

Score: 5

Looks like your problem is one of escaping. Single 6 quotes (') in PHP work differently than double 5 quotes ("). It's a lot like in Perl, where 4 variable interpolation does not happen in 3 singly-quoted strings, and the dollar sign 2 ($) is not a meta-character:

print "\$"; # prints $
print '\$'; # prints \$

Also, Perl's 1 character classes will simplify your code:

$tmpStr = preg_replace('/([?#^&*()$\\/])/', '\\\\$1', $tmpStr);

Score: 4

The $ sign has to be escaped with itself 1 so

$tmpStr=preg_replace("/$$/", "\$", $tmpStr);

I would also advise to look to addslashes instead.

Score: 2

Yes, it does seem that \\$ is seen by PHP as 4 $ in a double-quoted string. That means you 3 have to make PHP see a \$ by saying \\\$ .

I just 2 tried preg_replace("/\\\$$k\\\$/", $v, $data) and indeed it works (replaces occurrences 1 of $KEY$ with VALUE.

Score: 0

IIRC you replace $ with $. So it should 1 be $$

You can also try

$tmpStr=preg_replace('/\$/', '\$', $tmpStr);

Score: 0

isn't it true that PHP sees \$ as $ ? I 11 haven't tested this out, it might go like 10 this;

php is first, and replaces your "/\$/" with 9 "/$/" then the preg engine does it's magic 8 .. unfortunately, $ is a regular expression 7 operator ( I believe it matches the end 6 of a string?), so it doesn't find the $-characters 5 in your text but will

I think, what you 4 need to do, is to doubble escape the $-character 3 like so;

$tmpStr=preg_replace("/\$/", "\$", $tmpStr);

Also 2 .. in this case, I would have just used 1 str_replace()

Source: stackoverflow.com

[ACCEPTED]-How to escape $ in PHP using preg_replace?-preg-replace

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