[ACCEPTED]-Check if a String Ends with a Number in PHP-numbers
return is_numeric(substr($string, -1, 1));
This only checks to see if the last character 5 in the string is numerical, if you want 4 to catch and return multidigit numbers, you 3 might have to use a regex.
An appropriate 2 regex would be /[0-9]+$/ which will grab a numerical 1 string if it is at the end of a line.
$test="abc123";
//$test="abc123n";
$r = preg_match_all("/.*?(\d+)$/", $test, $matches);
//echo $r;
//print_r($matches);
if($r>0) {
echo $matches[count($matches)-1][0];
}
the regex is explained as follows:
.*? - this 8 will take up all the characters in the string 7 from the start up until a match for the 6 subsequent part is also found.
(\d+)$ - this 5 is one or more digits up until the end of 4 the string, grouped.
without the ? in the 3 first part, only the last digit will be 2 matched in the second part because all digits 1 before it would be taken up by the .*
To avoid potential undefined index error 1 use
is_numeric($code[strlen($code) - 1])
instead.
in my opinion The simple way to find a string 1 ends with number is
$string = "string1";
$length = strlen($string)-1;
if(is_numeric($string[$length]))
{
echo "String Ends with Number";
}
Firstly, Take the length of string, and check if 4 it is equal to zero (empty) then return false. Secondly, check with 3 built-in function on the last character 2 $len-1.
is_numeric(var)returns boolean whether a variable is 1 a numeric string or not.
function endsWithNumber($string){
$len = strlen($string);
if($len === 0){
return false;
}
return is_numeric($string[$len-1]);
}
Tests:
var_dump(endsWithNumber(""));
var_dump(endsWithNumber("str123"));
var_dump(endsWithNumber("123str"));
Results:
bool(false)
bool(true)
bool(false)
This should work
function startsWithNumber(string $input):bool
{
$out = false; //assume negative response, to avoid using else
if(strlen($input)) {
$out = is_numeric($input[0]); //only if string is not empty, do this to avoid index related errors.
}
return $out;
}
0
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