[ACCEPTED]-Remove ^H and ^M characters from a file using Linux shell scripting-shell
What you're seeing there are control characters, you 1 simply could delete them with tr
cat your_file |
tr -d '\b\r'
this is better:
tr -d '\b\r' < your_file
Two methods come to mind immediately:
tr -d control+v control+hsed 's/control+v control+h//g'
Here's 1 both in action:
$ od -c test
0000000 \b h e l l o \b t h e r e \b \n
0000016
$ sed 's/^H//g' < test | od -c
0000000 h e l l o t h e r e \n
0000013
$ tr -d ^H < test | od -c
0000000 h e l l o t h e r e \n
0000013
For removing ^M characters appearing at 4 the end of every line, I usually do this 3 in vi editor.
:%s/.$//g
It just removes the last character 2 of every line irrespective of what the character 1 is. This solved my provlem.
Use sed utility.
See below as per examples:
sed 's/%//' file > newfile
echo "82%%%" | sed 's/%*$//'
echo "68%" | sed "s/%$//" #assume % is always at the end.
0
You can remove all control characters by 2 using tr, e.g.
tr -d "[:cntrl:]" file.txt
To exclude some of them (like 1 line endings), check: Removing control characters from a file.
if you want to change original file, do 2 this:
sed -i '.bak' 's/^M//g ; s/^H//g' test.md
(^M is control+v control+m)
(^H is control+v control+h)
much file, you can 1 do this:
find source -name '*.md' | xargs sed -i '.bak' 's/^M//g ; s/^H//g'
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