[ACCEPTED]-Get Correct keyCode for keypad(numpad) keys-jquery

Use the keypress handler:

[somelement].onkeypress = function(e){
  e = e || event;
  console.log(String.fromCharCode(e.keyCode));
}

See also: this W3C testdocument

if you want to 2 use the keyup or keydown handler, you can subtract 48 1 from e.keyCode to get the number (so String.fromCharCode(e.keyCode-48))

I fixed the issue using following javascript 3 code. The numpad keys lie between 96 to 105. but 2 the real numbers are less 48 from the numpad 1 values. Works with keyup or keydown handler.

var keyCode = e.keyCode || e.which;
if (keyCode >= 96 && keyCode <= 105) {
  // Numpad keys
  keyCode -= 48;
}
var number = String.fromCharCode(keyCode);

There is a way to do this with keydown, if 15 keypress is not workable due to event canceling 14 needs, etc. Use an if() statement with this 13 test:

parseInt(event.keyIdentifier.substring(2),16) > 47 && parseInt(event.keyIdentifier.substring(2),16) < 58

OR, with jQuery events:

parseInt(event.originalEvent.keyIdentifier.substring(2),16) > 47 && parseInt(event.originalEvent.keyIdentifier.substring(2),16) < 58

These examples 12 assume "event" is the keydown event. keyIdentifier 11 is a hexidecimal number that represents 10 the unicode value for the related char. Using 9 keyIdentifier, numbers from the numberpad 8 / keypad AND the numbers above your QWERTY 7 keyboard will all have the same values, 48 6 - 57 (U+0030 - U+0039), even with the keyDown 5 event.

Unicode values in the browsers will 4 look like U+0030 or U+002F. Parse this string 3 to only get the hexidecimal value, then 2 use parseInt() with a radix of 16 to convert 1 it to base-10.

Ok. But In Firfox Gecko It doesn't work. I 1 use bellow code and I'm happy with it :)

[somelement].onkeypress = function(e){
  var singleChar=e.key || String.fromCharCode(e.keyCode);
  console.log(singleChar);
}

event.charCode at onKeyPress return the 6 same code when press a number in keyboard 5 and keypad. but event.keyCode at onKeyDown 4 (or up) return different code. => get char: use 3 event.charCode at onKeyPress event event.preventDefault() (or 2 event.returnValue=false on IE) for number 1 use event.keyCode at onKeyDown event

I think a safer way is not assuming the 7 value keys that will be used. You could 6 get the working value by the KeyboardEvent 5 object and access its properties "DOM_VK_*". Let 4 me give you an example.

 const kcN0=KeyboardEvent.DOM_VK_0;//get the 0 key value (commonly,48)
 const kcN9=KeyboardEvent.DOM_VK_9;//get the 9 key value (commonly, 57)
 const kcNPad0=KeyboardEvent.DOM_VK_NUMPAD0;//get the NUMPAD 0 key value (commonly,96)
 const kcNPad9=KeyboardEvent.DOM_VK_NUMPAD9;//get the NUMPAD 9 key value (commonly,105)
 const kcNPad_L=KeyboardEvent.DOM_KEY_LOCATION_NUMPAD;//get the key location of NUMPAD (commonly, 3)

and evalute the event 3 variable "kbEv"

let pressKeyCode=(kbEv.which||kbEv.keyCode); if( kbEv.location===kcNPad_L && pressKeyCode>=kcNumP0 && pressKeyCode<=kcNumP9 ) pressKeyCode=kcN0+kcNPad9-pressKeyCode;

I've only assumed that from 2 0 to 9 will be sequential in those two disjoint 1 numerical digit pattern set.