[ACCEPTED]-include external .js file in node.js app-node.js
To place an emphasis on what everyone else 9 has been saying var foo
in top level does not create 8 a global variable. If you want a global 7 variable then write global.foo
. but we all know globals 6 are evil.
If you are someone who uses globals 5 like that in a node.js project I was on 4 I would refactor them away for as there 3 are just so few use cases for this (There 2 are a few exceptions but this isn't one).
// Declare application
var app = require('express').createServer();
// Declare usefull stuff for DB purposes
var mongoose = require('mongoose');
var Schema = mongoose.Schema;
var ObjectId = Schema.ObjectId;
require('./models/car.js').make(Schema, mongoose);
in 1 car.js
function make(Schema, mongoose) {
// Define Car model
CarSchema = new Schema({
brand : String,
type : String
});
mongoose.model('Car', CarSchema);
}
module.exports.make = make;
The correct answer is usually to use require, but 3 in a few cases it's not possible.
The following 2 code will do the trick, but use it with 1 care:
var fs = require('fs');
var vm = require('vm');
var includeInThisContext = function(path) {
var code = fs.readFileSync(path);
vm.runInThisContext(code, path);
}.bind(this);
includeInThisContext(__dirname+"/models/car.js");
Short answer:
// lib.js
module.exports.your_function = function () {
// Something...
};
// app.js
require('./lib.js').your_function();
0
you can put
var mongoose = require('mongoose');
var Schema = mongoose.Schema;
at the top of your car.js file 2 for it to work, or you can do what Raynos 1 said to do.
If you just want to test a library from 1 the command line, you could do:
cat somelibrary.js mytestfile.js | node
This approach works for me in Node.js, Is there any problem with this one?
File 'include.js':
fs = require('fs');
File 'main.js':
require('./include.js');
fs.readFile('./file.json', function (err, data) {
if (err) {
console.log('ERROR: file.json not found...')
} else {
contents = JSON.parse(data)
};
})
0
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