[ACCEPTED]-How to find maximum value of set of variables-max

Accepted answer

Score: 24

In Java, you can use Math.max like this:

double maxStock = Math.max( firstQuarter, Math.max( secondQuarter, Math.max( thirdQuarter, fourthQuarter ) ) );

Not the 3 most elegant, but it will work.

Alternatively, for 2 a more robust solution define the following 1 function:

private double findMax(double... vals) {
   double max = Double.NEGATIVE_INFINITY;

   for (double d : vals) {
      if (d > max) max = d;
   }

   return max;
}

Which you can then call by:

double maxStock = findMax(firstQuarter, secondQuarter, thirdQuarter, fourthQuarter);

Score: 4

One method to rule them all

public static <T extends Comparable<T>> T max(T...values) {
    if (values.length <= 0)
        throw new IllegalArgumentException();

    T m = values[0];
    for (int i = 1; i < values.length; ++i) {
        if (values[i].compareTo(m) > 0)
            m = values[i];
    }

    return m;
}

Score: 2

With primitive variables the best choice 5 maybe with Arrays or Collections:

Arrays:

double [ ] data = { firstQuarter , secondQuarter , thirdQuarter , fourtQuarter ) ;
Arrays . sort ( data ) [ 3 ] ;

Collections:

List<Double> data = new Arraylist<Double>();
data.add(firstQuarter);
data.add(secondQuarter);
data.add(thirdQuarter);
data.add(foutQuarter);
Collections.sort(data);
data.get(3);

And 4 if you work with Objects you may use Collections 3 with a Comparator:

class Quarter {
    private double value;
    private int order;

    // gets and sets
}

And to get the max value:

List<Quarter> list = new ArrayList<Quarter>();
Quarter fisrt = new Quarter();
first.setValue(firstQuarter);
first.setOrder(1);
list.add(first);
// Do the same with the other values
Collections.sort(list, new Comparator<Quarter>(){
    compare(Object o1, Object o2){
        return Double.valueOf(o1.getValue()).compareTo(o2.getValue());
    }
}

This 2 may be more complex, but if you working 1 with objects i think is better to work.

Score: 2

I believe now in Java 8 the most concise 1 version would look like this:

DoubleStream.of(firstQuarter , secondQuarter , thirdQuarter , fourtQuarter).max();

Score: 1

double [ ] data = { firstQuarter , secondQuarter , thirdQuarter , fourtQuarter ) ;
Arrays . sort ( data ) [ 3 ] ;

Score: 1

A little late to the party, but for anyone 9 else viewing this question, java 8 has primitive 8 stream types that implement exactly this

Collection<Integer> values = new ArrayList<>();
OptionalInt max = values.stream().mapToInt((x) -> x).max();

mapToInt 7 is the key function that describes how to 6 convert the input to an integer type. The 5 resulting stream then has additional aggregators 4 and collectors specific to integer types, one 3 of the being max().

The result value can then 2 be extracted from the OptionalInt, if the operation 1 was successful

Score: 0

Max = firstQuarter;
If(secondQuarter > max)
   Max = secondQuarter;

... And so on

Source: stackoverflow.com

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