[ACCEPTED]-C# - Convert WPF Image.source to a System.Drawing.Bitmap-bitmap

Accepted answer

Score: 25

Actually you don't need to use unsafe code. There's 1 an overload of CopyPixels that accepts an IntPtr:

public static System.Drawing.Bitmap BitmapSourceToBitmap2(BitmapSource srs)
{
    int width = srs.PixelWidth;
    int height = srs.PixelHeight;
    int stride = width * ((srs.Format.BitsPerPixel + 7) / 8);
    IntPtr ptr = IntPtr.Zero;
    try
    {
        ptr = Marshal.AllocHGlobal(height * stride);
        srs.CopyPixels(new Int32Rect(0, 0, width, height), ptr, height * stride, stride);
        using (var btm = new System.Drawing.Bitmap(width, height, stride, System.Drawing.Imaging.PixelFormat.Format1bppIndexed, ptr))
        {
            // Clone the bitmap so that we can dispose it and
            // release the unmanaged memory at ptr
            return new System.Drawing.Bitmap(btm);
        }
    }
    finally
    {
        if (ptr != IntPtr.Zero)
            Marshal.FreeHGlobal(ptr);
    }
}

Score: 3

That example worked for me:

    public static Bitmap ConvertToBitmap(BitmapSource bitmapSource)
    {
        var width = bitmapSource.PixelWidth;
        var height = bitmapSource.PixelHeight;
        var stride = width * ((bitmapSource.Format.BitsPerPixel + 7) / 8);
        var memoryBlockPointer = Marshal.AllocHGlobal(height * stride);
        bitmapSource.CopyPixels(new Int32Rect(0, 0, width, height), memoryBlockPointer, height * stride, stride);
        var bitmap = new Bitmap(width, height, stride, PixelFormat.Format32bppPArgb, memoryBlockPointer);
        return bitmap;
    }

Score: 2

Are your ImageSource not a BitmapSource? If 6 your loading the images from files they 5 should be.

Reply to your comment:

Sounds like 4 they should be BitmapSource then, BitmapSource 3 is a subtype of ImageSource. Cast the ImageSource 2 to BitmapSource and follow one of those 1 blogposts.

Score: 1

You don't need a BitmapSourceToBitmap method at all. Just do 2 the following after creating your memory 1 stream:

mem.Position = 0;  
Bitmap b = new Bitmap(mem);

Source: stackoverflow.com

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