[ACCEPTED]-How do I "cut" out part of a string with a regex?-regex

Accepted answer

Score: 11

Error checking left as an exercise...

        Regex regex = new Regex( @"\d+" );
        MatchCollection matches = regex.Matches( "changed from 1 to 10" );
        int num1 = int.Parse( matches[0].Value );
        int num2 = int.Parse( matches[1].Value );

Score: 4

Matching only exactly the string "changed 1 from x to y":

string pattern = @"^changed from ([0-9]+) to ([0-9]+)$";
Regex r = new Regex(pattern);
Match m = r.match(text);
if (m.Success) {
   Group g = m.Groups[0];
   CaptureCollection cc = g.Captures;

   int from = Convert.ToInt32(cc[0]);
   int to = Convert.ToInt32(cc[1]);

   // Do stuff
} else {
   // Error, regex did not match
}

Score: 2

In your regex put the fields you want to 3 record in parentheses, and then use the 2 Match.Captures property to extract the matched fields.

There's 1 a C# example here.

Score: 1

Use named capture groups.

Regex r = new Regex("*(?<FirstNumber>[0-9]{1,2})*(?<SecondNumber>[0-9]{1,2})*");
 string input = "changed from 1 to 10";
 string firstNumber = "";
 string secondNumber = "";

 MatchCollection joinMatches = regex.Matches(input);

 foreach (Match m in joinMatches)
 {
  firstNumber= m.Groups["FirstNumber"].Value;
  secondNumber= m.Groups["SecondNumber"].Value;
 }

Get Expresson to help you 1 out, it has an export to C# option.

DISCLAIMER: Regex is probably not right (my copy of expresso expired :D)

Score: 0

Here is a code snippet that does almost what I 1 wanted:

using System.Text.RegularExpressions;

string text = "changed from 1 to 10";
string pattern = @"\b(?<digit>\d+)\b";
Regex r = new Regex(pattern);
MatchCollection mc = r.Matches(text);
foreach (Match m in mc) {
    CaptureCollection cc = m.Groups["digit"].Captures;
    foreach (Capture c in cc){
        Console.WriteLine((Convert.ToInt32(c.Value)));
    }
}

Source: stackoverflow.com

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